3.14r^2=100.48r

Solution for 3.14r^2=100.48r equation:

3.14r^2=100.48r

We move all terms to the left:

3.14r^2-(100.48r)=0

We add all the numbers together, and all the variables

3.14r^2-(+100.48r)=0

We get rid of parentheses

3.14r^2-100.48r=0

a = 3.14; b = -100.48; c = 0;
Δ = b2-4ac
Δ = -100.482-4·3.14·0
Δ = 10096.2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-100.48)-\sqrt{10096.2304}}{2*3.14}=\frac{100.48-\sqrt{10096.2304}}{6.28}
$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-100.48)+\sqrt{10096.2304}}{2*3.14}=\frac{100.48+\sqrt{10096.2304}}{6.28}
$